**Prof. Dr. Jean-Pierre Luminet**

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**First email**: 20 March 2012

Dear Prof. Dr. Jean-Pierre Luminet:

I am reading, thinking and ingesting your work as best I can.

I have made reference to you in an article here:

https://81018.com/2012/05/05/wikipedia/#History

Your critical review is appreciated. I know there are some very large leaps within it.

I also have a series of baby questions I hope you might answer:

1. Who do you believe has the best calculation for the diameter of the observable universe? Why? I have seen a rather imposing range.

2. With your quick calculation below of the number of base-2 notations, what is that 3/3/3/4 formula? How many notations going within? How many notations going out?

3. Are you involved with the ASTRON project with the Netherlands Institute for Radio Astronomy and IBM?

Thanks.

–Bruce

**Reply**: Wednesday, July 17, 2013

**With permission the following response from Jean-Pierre Luminet is posted**:

“I tried to understand the discrepancy between my calculation and that of Joe Kolecki. The reason is simple. Joe took as a maximum length in the universe the so-called Hubble radius, whereas in cosmology the pertinent distance is the diameter of the observable universe (delimited by the particle horizon), now estimated to be 93 billion light years, namely 8.8 10^26 m. In my first calculation giving the result 206, I took the approximate 10^27 m, and for the Planck length 10^(-35) m instead of the exact 1.62 10^(-35) m. Thus the right calculation gives 8.8 10^26 m / 1.62 10^(-35) m = 5.5 10^(61) = 2^(205.1). Thus the number of steps is 205 instead of 206. You can quote my calculation in your website.” – Jean-Pierre Luminet, Directeur de recherches au CNRS, Laboratoire Univers et Théories (LUTH), Observatoire de Paris, 92195 Meudon Cedex http://luth.obspm.fr/~luminet/

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